TI Hitunglah bilangan dibawah ini: [Bobot: 25] a. 101010(2) + 10010(2) = ............. (2) b. 517(8) + 154(8) = ............. (8) c. BD4(16) - 98A(16) = ............. (16)

kurtrodriguezulv – March 11, 2023

Hitunglah bilangan dibawah ini: [Bobot: 25]
a. 101010(2) + 10010(2) = ............. (2)
b. 517(8) + 154(8) = ............. (8) c. BD4(16) - 98A(16) = ............. (16)

Jawaban dan Penjelasan:

a. 101010(2) + 10010(2) = 111100(2)

101010(2) = (1x2⁵) + (0x2⁴) + (1x2³) + (0x2²) + (1 x2¹) + (0×2⁰) = 42(10)

10010(2) = (1 x2⁴) + (0x2³) + (0x2²) + (1x2¹) + (0x2⁰) = 18(10)

42(10)+18(10) = 60(10)

60(10) = 111100(2)

b. 517(8) + 154(8) = 673(8)

517(8) = 517 = (5x8²) + (1x8¹) + (7x8⁰) = 335(10)

154 = (1X8²) + (5x8¹) + (4x8⁰) = 108(10)

335(10)+108(10) = 443(10)

443(10) = 673(8)

c. BD4(16) - 98A(16) = 166C(16)

BD4(16) = (11x16²) + (13x16¹) + (4x16⁰) = 3028(10)

98A(16) = (9x16²) + (8x16¹) + (10x16⁰) = 2442(10)

3028(10)+2442(10) = 5740(10)

5740(10) = 166C(16)

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